C Pointer To String And Char Catch 22 Stack Overflow A pointer in c or c may point either to a single item (a single char) or to the first in an array of items (char[]). so a char *p[10]; definition may point to 10 single characters or 10 arrays (i.e. 10 strings). More specifically, this part (*(s1 i)) if it possible to force it to sequence through entire array character by character via pointer, for example, *s1 . my task to do this function comparestrings without index array []: int i = 0, answer;.

C Integer Array To Char Pointer String Stack Overflow The char *ptrchar; actually points to the beginning of the string (char array), and thus that is the pointer to that string, so when you do like ptrchar[x] for example, you actually access the memory location x times after the beginning of the char (aka from where ptrchar is pointing to). I'm currently studying c and i'm trying to just print the contents of a string array. i'm using pnames to point to the first char pointer and iterating from there. a more proper approach would use this pointer, get a char* each time and use printf("%s", pnames[i]) to print a whole string. When you use a string constant like "hello" in your program, the compiler automatically constructs the array for you, as a convenience. next we have the character pointer type, char *. you called this a "string to a char array", but it's really a pointer to a single char. It's not ok to return a non const pointer to a literal. if you want to return a modifiable (non const) string, declare it a static char[]. or better, return a copy: don't forget to free afterwards. strdup is non iso but available almost everywhere (except msvc, i believe). strdup not available on msvc ? are you sure ?.

Print Char Pointer Value In C Stack Overflow When you use a string constant like "hello" in your program, the compiler automatically constructs the array for you, as a convenience. next we have the character pointer type, char *. you called this a "string to a char array", but it's really a pointer to a single char. It's not ok to return a non const pointer to a literal. if you want to return a modifiable (non const) string, declare it a static char[]. or better, return a copy: don't forget to free afterwards. strdup is non iso but available almost everywhere (except msvc, i believe). strdup not available on msvc ? are you sure ?. C : pointer to string and char catch 22to access my live chat page, on google, search for "hows tech developer connect"as promised, i'm going to share a hi. In my output the pointer is altered and * the string prints out fine. why? * word = "cat"; printf("pointer: %p\n", word); printf("string: %s\n", word); * * it only partially works though as altering a single element * leads to a segmentation fault * word[0] = '!'; printf("pointer: %p\n", word); printf("string: %s\n", word); free(word); }. You might want to allocate some memory for the char pointer to point to, before you copy data to the memory section the char pointer points to. strcat is going to write characters, starting with the nul at the end of the string t points to. in your first example, t is uninitialized i.e. points to who knows what. I wrote out a function to allow me to grab a piece of the string 32 bits at a time and convert that into a number while using an offset: uint fast32 t get32bitint(const char *data, int offset = 0).