
How To Call An Async Method Synchronously In C You can get the taskawaiter with the getawaiter method, and wait synchronously for the completion of the task with the blocking getresult method: string code = generatecodeasync().getawaiter().getresult();. In c#, you can call an asynchronous function from a synchronous function by using the result property or the wait method of the task object. however, it's important to note that blocking the synchronous function to wait for the asynchronous operation to complete can lead to potential deadlocks in certain scenarios, such as ui applications.

C Async Method Runs Synchronously Stack Overflow The best answer to the question "how can i call an async method synchronously" is "don't". there are hacks to try to force it to work, but they all have very subtle pitfalls. instead, back up and fix the code that makes you "need" to do this. You can call any asynchronous method from synchronous code, that is, until you need to await on them, in which case they have to be marked as async too. as a lot of people are suggesting here, you could call wait() or result on the resulting task in your synchronous method, but then you end up with a blocking call in that method, which sort of. In my application there is an async method which calls an api and from the result i need to send to a queuing system. i don't need to await the result. but the method to push the message is a synchronous one. what's the best way we can implement it?. What's the correct way to implement the latter, sync method so it doesn't show the "method will run synchronously" warning? return articles.where(a => a.articleid == articleid).firstordefault(); the async await keywords don't matter. the real question is "does your method need to return a task or task

C Async Method Call Running Synchronously Even With Await Operator In my application there is an async method which calls an api and from the result i need to send to a queuing system. i don't need to await the result. but the method to push the message is a synchronous one. what's the best way we can implement it?. What's the correct way to implement the latter, sync method so it doesn't show the "method will run synchronously" warning? return articles.where(a => a.articleid == articleid).firstordefault(); the async await keywords don't matter. the real question is "does your method need to return a task or task