List Fastapi Curated By Datarm Medium The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings. other than that i think the only difference is speed: it looks like it's a little faster the first way. try it yourself with timeit.timeit () or preferably timeit.repeat (). I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getsingle(arr): from collections import counter c = counte.

Datarm On Medium Curated Some Lists Since a list comprehension creates a list, it shouldn't be used if creating a list is not the goal; it shouldn't be used simply to write a one line for loop; so refrain from writing [print(x) for x in range(5)] for example. Caveats linear time complexity in list length an index call checks every element of the list in order, until it finds a match. if the list is long, and if there is no guarantee that the value will be near the beginning, this can slow down the code. this problem can only be completely avoided by using a different data structure. So, in current java terminology: list.of is an unmodifiable view collection and list.copyof is a normal unmodifiable collection, both structurally unmodifiable via the collection object itself. But that's what we want in order to get the unique elements from a list with duplicates, we want to .append them into a new list only when we they came across for a fist time. so we really want to evaluate used.append(x) only when x is not in used, maybe if there is a way to turn this none value into a truthy one we will be fine, right?.

List Fastapi Curated By Douglas Ausech Medium So, in current java terminology: list.of is an unmodifiable view collection and list.copyof is a normal unmodifiable collection, both structurally unmodifiable via the collection object itself. But that's what we want in order to get the unique elements from a list with duplicates, we want to .append them into a new list only when we they came across for a fist time. so we really want to evaluate used.append(x) only when x is not in used, maybe if there is a way to turn this none value into a truthy one we will be fine, right?. When reading, list is a reference to the original list, and list[:] shallow copies the list. when assigning, list (re)binds the name and list[:] slice assigns, replacing what was previously in the list. also, don't use list as a name since it shadows the built in. How can i check if a list has any duplicates and return a new list without duplicates?. For handling a few strings in separate variables, see how do i append one string to another in python?. for the opposite process creating a list from a string see how do i split a string into a list of characters? or how do i split a string into a list of words? as appropriate. Note that the question was about pandas tolist vs to list. pandas.dataframe.values returns a numpy array and numpy indeed has only tolist. indeed, if you read the discussion about the issue linked in the accepted answer, numpy's tolink is the reason why pandas used tolink and why they did not deprecate it after introducing to list.